95992828九五至尊2

五1八个常用的sql语句,应聘中常用的SQL语句

三月 20th, 2019  |  九五至尊老品牌值信赖

Student(S#,Sname,Sage,Ssex) 学生表
Course(C#,Cname,T#) 课程表
SC(S#,C#,score) 成绩表
Teacher(T#,Tname) 教师表

Student(S#,Sname,Sage,Ssex)
学生表
Course(C#,Cname,T#) 课程表
SC(S#,C#,score) 成绩表
Teacher(T#,Tname) 教师表

问题:
一 、查询“001”课程比“002”课程战表高的具有学员的学号;
  select a.S# from (select s#,score from SC where C#=’001′) a,(select
s#,score
  from SC where C#=’002′) b
  where a.score>b.score and a.s#=b.s#;
② 、查询平均成绩超过六二十分的同学的学号和平均成绩;
    select S#,avg(score)
    from sc
    group by S# having avg(score) >60;
③ 、查询全体同学的学号、姓名、选课数、总战表;
  select Student.S#,Student.Sname,count(SC.C#),sum(score)
  from Student left Outer join SC on Student.S#=SC.S#
  group by Student.S#,Sname
④ 、查询姓“李”的教职工的个数;
  select count(distinct(Tname))
  from Teacher
  where Tname like ‘李%’;
五 、查询没学过“叶平”老师课的同班的学号、姓名;
    select Student.S#,Student.Sname
    from Student 
    where S# not in (select distinct( SC.S#) from SC,Course,Teacher
where  SC.C#=Course.C# and Teacher.T#=Course.T# and
Teacher.Tname=’叶平’);
六 、查询学过“001”并且也学过数码“002”课程的同室的学号、姓名;
  select Student.S#,Student.Sname from Student,SC where
Student.S#=SC.S# and SC.C#=’001’and exists( Select * from SC as
SC_2 where SC_2.S#=SC.S# and SC_2.C#=’002′);
七 、查询学过“叶平”老师所教的全体课的校友的学号、姓名;
  select S#,Sname
  from Student
  where S# in (select S# from SC ,Course ,Teacher where
SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname=’叶平’
group by S# having count(SC.C#)=(select count(C#) from
Course,Teacher  where Teacher.T#=Course.T# and Tname=’叶平’));
⑧ 、查询课程编号“002”的实际业绩比课程编号“001”课程低的享有同学的学号、姓名;
  Select S#,Sname from (select Student.S#,Student.Sname,score ,(select
score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#=’002′)
score2
  from Student,SC where Student.S#=SC.S# and C#=’001′) S_2 where
score2 <score;
九 、查询全部科目成绩小于六12分的同桌的学号、姓名;
  select S#,Sname
  from Student
  where S# not in (select Student.S# from Student,SC where
S.S#=SC.S# and score>60);
⑩ 、查询没有学全全体课的同学的学号、姓名;
    select Student.S#,Student.Sname
    from Student,SC
    where Student.S#=SC.S# group by  Student.S#,Student.Sname having
count(C#) <(select count(C#) from Course);
1一 、查询至少有一门课与学号为“1001”的同桌所学相同的同桌的学号和姓名;
    select S#,Sname from Student,SC where Student.S#=SC.S# and C# in
select C# from SC where S#=’1001′;
1贰 、查询至少学过学号为“001”同学全部一门课的别的同学学号和姓名;
    select distinct SC.S#,Sname
    from Student,SC
    where Student.S#=SC.S# and C# in (select C# from SC where
S#=’001′);
1③ 、把“SC”表中“叶平”老师教的课的实际业绩都更改为此课程的平分战表;
    update SC set score=(select avg(SC_2.score)
    from SC SC_2
    where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C#
and Course.T#=Teacher.T# and Teacher.Tname=’叶平’);
1肆 、查询和“1002”号的同班学习的学科完全相同的其余同学学号和姓名;
    select S# from SC where C# in (select C# from SC where
S#=’1002′)
    group by S# having count(*)=(select count(*) from SC where
S#=’1002′);
1五 、删除学习“叶平”老师课的SC表记录;
    Delect SC
    from course ,Teacher 
    where Course.C#=SC.C# and Course.T#= Teacher.T# and
Tname=’叶平’;
1陆 、向SC表中插入一些笔录,这个记录须求符合以下原则:没有上过编号“003”课程的同桌学号、② 、
    号课的平均战表;
    Insert SC select S#,’002′,(Select avg(score)
    from SC where C#=’002′) from Student where S# not in (Select S#
from SC where C#=’002′);
1七 、按平均战绩从高到低展现全部学员的“数据库”、“企管”、“克罗地亚(Croatia)语”三门的科目战绩,按如下方式彰显:
学生ID,,数据库,企管,罗马尼亚(România)语,有效课程数,有效平均分
    SELECT S# as 学生ID
        ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#=’004′) AS
数据库
        ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#=’001′) AS
企业管理
        ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#=’006′) AS
英语
        ,COUNT(*) AS 有效课程数, AVG(t.score) AS 平均成绩
    FROM SC AS t
    GROUP BY S#
    ORDER BY avg(t.score) 
1八 、查询各科战表最高和压低的分:以如下情势显得:课程ID,最高分,最低分
    SELECT L.C# As 课程ID,L.score AS 最高分,R.score AS 最低分
    FROM SC L ,SC AS R
    WHERE L.C# = R.C# and
        L.score = (SELECT MAX(IL.score)
                      FROM SC AS IL,Student AS IM
                      WHERE L.C# = IL.C# and IM.S#=IL.S#
                      GROUP BY IL.C#)
        AND
        R.Score = (SELECT MIN(IR.score)
                      FROM SC AS IR
                      WHERE R.C# = IR.C#
                  GROUP BY IR.C#
                    );
1九 、按各科平均战表从低到高和及格率的比重从高到低依次
    SELECT t.C# AS 课程号,max(course.Cname)AS
课程名,isnull(AVG(score),0) AS 平均战绩
        ,100 * SUM(CASE WHEN  isnull(score,0)>=60 THEN 1 ELSE 0
END)/COUNT(*) AS 及格百分数
    FROM SC T,Course
    where t.C#=course.C#
    GROUP BY t.C#
    ORDER BY 100 * SUM(CASE WHEN  isnull(score,0)>=60 THEN 1 ELSE 0
END)/COUNT(*) DESC
20、查询如下课程平均成绩和及格率的比例(用”1行”突显):
企管(001),马克思(002),OO&UML (003),数据库(004)
    SELECT SUM(CASE WHEN C# =’001′ THEN score ELSE 0 END)/SUM(CASE C#
WHEN ‘001’ THEN 1 ELSE 0 END) AS 企管平均分
        ,100 * SUM(CASE WHEN C# = ‘001’ AND score >= 60 THEN 1 ELSE
0 END)/SUM(CASE WHEN C# = ‘001’ THEN 1 ELSE 0 END) AS
企管及格百分数
        ,SUM(CASE WHEN C# = ‘002’ THEN score ELSE 0 END)/SUM(CASE C#
WHEN ‘002’ THEN 1 ELSE 0 END) AS 马克思平均分
        ,100 * SUM(CASE WHEN C# = ‘002’ AND score >= 60 THEN 1 ELSE
0 END)/SUM(CASE WHEN C# = ‘002’ THEN 1 ELSE 0 END) AS
马克思及格百分数
        ,SUM(CASE WHEN C# = ‘003’ THEN score ELSE 0 END)/SUM(CASE C#
WHEN ‘003’ THEN 1 ELSE 0 END) AS UML平均分
        ,100 * SUM(CASE WHEN C# = ‘003’ AND score >= 60 THEN 1 ELSE
0 END)/SUM(CASE WHEN C# = ‘003’ THEN 1 ELSE 0 END) AS UML及格百分数
        ,SUM(CASE WHEN C# = ‘004’ THEN score ELSE 0 END)/SUM(CASE C#
WHEN ‘004’ THEN 1 ELSE 0 END) AS 数据库平均分
        ,100 * SUM(CASE WHEN C# = ‘004’ AND score >= 60 THEN 1 ELSE
0 END)/SUM(CASE WHEN C# = ‘004’ THEN 1 ELSE 0 END) AS
数据库及格百分数
  FROM SC
2一 、查询分裂老师所教分裂科目平均分从高到低展现
  SELECT max(Z.T#) AS 教师ID,MAX(Z.Tname) AS 教授姓名,C.C# AS
课程ID,MAX(C.Cname) AS 课程名称,AVG(Score) AS 平均成绩
    FROM SC AS T,Course AS C ,Teacher AS Z
    where T.C#=C.C# and C.T#=Z.T#
  GROUP BY C.C#
  ORDER BY AVG(Score) DESC
2② 、查询如下课程成绩第 3 名到第 6
名的学生战表单:企管(001),马克思(002),UML
(003),数据库(004)
    [学生ID],[学员姓名],企管,马克思,UML,数据库,平均战表
    SELECT  DISTINCT top 3
      SC.S# As 学生学号,
        Student.Sname AS 学生姓名 ,
      T1.score AS 企管,
      T2.score AS 马克思,
      T3.score AS UML,
      T4.score AS 数据库,
      ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) +
ISNULL(T4.score,0) as 总分
      FROM Student,SC  LEFT JOIN SC AS T1
                      ON SC.S# = T1.S# AND T1.C# = ‘001’
            LEFT JOIN SC AS T2
                      ON SC.S# = T2.S# AND T2.C# = ‘002’
            LEFT JOIN SC AS T3
                      ON SC.S# = T3.S# AND T3.C# = ‘003’
            LEFT JOIN SC AS T4
                      ON SC.S# = T4.S# AND T4.C# = ‘004’
      WHERE student.S#=SC.S# and
      ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) +
ISNULL(T4.score,0)
      NOT IN
      (SELECT
            DISTINCT
            TOP 15 WITH TIES
            ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0)

问题:
壹 、查询“001”课程比“002”课程成绩高的兼具学员的学号;
select a.S# from (select s#,score from SC where C#=’001′) a,(select
s#,score
from SC where C#=’002′) b
where a.score>b.score and a.s#=b.s#;
二 、查询平均战表超乎伍拾伍分的同学的学号和平均成绩;
select S#,avg(score)
from sc
group by S# having avg(score) >60;
③ 、查询全体同学的学号、姓名、选课数、总成绩;
select Student.S#,Student.Sname,count(SC.C#),sum(score)
from Student left Outer join SC on Student.S#九五至尊老品牌值信赖,=SC.S#
group by Student.S#,Sname
肆 、查询姓“李”的教师的个数;
select count(distinct(Tname))
from Teacher
where Tname like ‘李%’;
伍 、查询没学过“叶平”老师课的同班的学号、姓名;
select Student.S#,Student.Sname
from Student
where S# not in (select distinct( SC.S#) from SC,Course,Teacher where
SC.C#=Course.C# and Teacher.T#=Course.T# and
Teacher.Tname=’叶平’);
⑥ 、查询学过“001”并且也学过数码“002”课程的同室的学号、姓名;
select Student.S#,Student.Sname from Student,SC where
Student.S#=SC.S# and SC.C#=’001’and exists( Select * from SC as
SC_2 where SC_2.S#=SC.S# and SC_2.C#=’002′);
柒 、查询学过“叶平”老师所教的全部课的同班的学号、姓名;
select S#,Sname
from Student
where S# in (select S# from SC ,Course ,Teacher where
SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname=’叶平’
group by S# having count(SC.C#)=(select count(C#) from Course,Teacher
where Teacher.T#=Course.T# and Tname=’叶平’));
八 、查询课程编号“002”的成绩比课程编号“001”课程低的兼具同学的学号、姓名;
Select S#,Sname from (select Student.S#,Student.Sname,score ,(select
score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#=’002′)
score2
from Student,SC where Student.S#=SC.S# and C#=’001′) S_2 where
score2 <score;
九 、查询全数科目战表小于五十五分的校友的学号、姓名;
select S#,Sname
from Student
where S# not in (select Student.S# from Student,SC where S.S#=SC.S#
and score>60);
十 、查询没有学全全部课的同室的学号、姓名;
select Student.S#,Student.Sname
from Student,SC
where Student.S#=SC.S# group by Student.S#,Student.Sname having
count(C#) <(select count(C#) from Course);
1① 、查询至少有一门课与学号为“1001”的同班所学相同的校友的学号和姓名;
select S#,Sname from Student,SC where Student.S#=SC.S# and C# in
select C# from SC where S#=’1001′;
1贰 、查询至少学过学号为“001”同学全部一门课的其余同学学号和姓名;
select distinct SC.S#,Sname
from Student,SC
where Student.S#=SC.S# and C# in (select C# from SC where
S#=’001′);
1叁 、把“SC”表中“叶平”老师教的课的成绩都改成为此课程的平分战表;
update SC set score=(select avg(SC_2.score)
from SC SC_2
where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C# and
Course.T#=Teacher.T# and Teacher.Tname=’叶平’);
1肆 、查询和“1002”号的同窗学习的课程完全相同的其余同学学号和姓名;
select S# from SC where C# in (select C# from SC where S#=’1002′)
group by S# having count(*)=(select count(*) from SC where
S#=’1002′);
1⑤ 、删除学习“叶平”老师课的SC表记录;
Delect SC
from course ,Teacher
where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname=’叶平’;
1六 、向SC表中插入一些笔录,那几个记录供给符合以下规则:没有上过编号“003”课程的同班学号、贰 、
号课的平均成绩;
Insert SC select S#,’002′,(Select avg(score)
from SC where C#=’002′) from Student where S# not in (Select S# from
SC where C#=’002′);
1⑦ 、按平均战绩从高到低展现全部学员的“数据库”、“企业管理”、“土耳其共和国(The Republic of Turkey)语”三门的教程成绩,按如下方式呈现:
学生ID,,数据库,企管,保加利亚共和国(The Republic of Bulgaria)语,有效课程数,有效平均分
SELECT S# as 学生ID
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#=’004′) AS 数据库
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#=’001′) AS 企业管理
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#=’006′) AS 英语
,COUNT(*) AS 有效课程数, AVG(t.score) AS 平均战表
FROM SC AS t
GROUP BY S#
ORDER BY avg(t.score)
1⑧ 、查询各科成绩最高和压低的分:以如下方式显得:课程ID,最高分,最低分
SELECT L.C# As 课程ID,L.score AS 最高分,R.score AS 最低分
FROM SC L ,SC AS R
WHERE L.C# = R.C# and
L.score = (SELECT MAX(IL.score)
FROM SC AS IL,Student AS IM
WHERE L.C# = IL.C# and IM.S#=IL.S#
GROUP BY IL.C#)
AND
R.Score = (SELECT MIN(IR.score)
FROM SC AS IR
WHERE R.C# = IR.C#
GROUP BY IR.C#
);
1九 、按各科平均成绩从低到高和及格率的比重从高到低依次
SELECT t.C# AS 课程号,max(course.Cname)AS 课程名,isnull(AVG(score),0)
AS 平均战绩
,100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0
END)/COUNT(*) AS 及格百分数
FROM SC T,Course
where t.C#=course.C#
GROUP BY t.C#
ORDER BY 100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0
END)/COUNT(*) DESC
20、查询如下课程平均战绩和及格率的比例(用”1行”展现):
企业管理(001),马克思(002),OO&UML (003),数据库(004)
SELECT SUM(CASE WHEN C# =’001′ THEN score ELSE 0 END)/SUM(CASE C# WHEN
‘001’ THEN 1 ELSE 0 END) AS 企业管理平均分
,100 * SUM(CASE WHEN C# = ‘001’ AND score >= 60 THEN 1 ELSE 0
END)/SUM(CASE WHEN C# = ‘001’ THEN 1 ELSE 0 END) AS
企管及格百分数
,SUM(CASE WHEN C# = ‘002’ THEN score ELSE 0 END)/SUM(CASE C# WHEN
‘002’ THEN 1 ELSE 0 END) AS 马克思平均分
,100 * SUM(CASE WHEN C# = ‘002’ AND score >= 60 THEN 1 ELSE 0
END)/SUM(CASE WHEN C# = ‘002’ THEN 1 ELSE 0 END) AS Marx及格百分数
,SUM(CASE WHEN C# = ‘003’ THEN score ELSE 0 END)/SUM(CASE C# WHEN
‘003’ THEN 1 ELSE 0 END) AS UML平均分
,100 * SUM(CASE WHEN C# = ‘003’ AND score >= 60 THEN 1 ELSE 0
END)/SUM(CASE WHEN C# = ‘003’ THEN 1 ELSE 0 END) AS UML及格百分数
,SUM(CASE WHEN C# = ‘004’ THEN score ELSE 0 END)/SUM(CASE C# WHEN
‘004’ THEN 1 ELSE 0 END) AS 数据库平均分
,100 * SUM(CASE WHEN C# = ‘004’ AND score >= 60 THEN 1 ELSE 0
END)/SUM(CASE WHEN C# = ‘004’ THEN 1 ELSE 0 END) AS 数据库及格百分数
FROM SC
2① 、查询不一致老师所教分裂科目平均分从高到低彰显
SELECT max(Z.T#) AS 教授ID,MAX(Z.Tname) AS 教授姓名,C.C# AS
课程ID,MAX(C.Cname) AS 课程名称,AVG(Score) AS 平均成绩
FROM SC AS T,Course AS C ,Teacher AS Z
where T.C#=C.C# and C.T#=Z.T#
GROUP BY C.C#
ORDER BY AVG(Score) DESC
2二 、查询如下课程成绩第 3 名到第 6
名的上学的小孩子战表单:企管(001),马克思(002),UML
(003),数据库(004)
[学生ID],[学生姓名],企管,马克思,UML,数据库,平均战绩
SELECT DISTINCT top 3
SC.S# As 学生学号,
Student.Sname AS 学生姓名 ,
T1.score AS 企管,
T2.score AS 马克思,
T3.score AS UML,
T4.score AS 数据库,
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) +
ISNULL(T4.score,0) as 总分
FROM Student,SC LEFT JOIN SC AS T1
ON SC.S# = T1.S# AND T1.C# = ‘001’
LEFT JOIN SC AS T2
ON SC.S# = T2.S# AND T2.C# = ‘002’
LEFT JOIN SC AS T3
ON SC.S# = T3.S# AND T3.C# = ‘003’
LEFT JOIN SC AS T4
ON SC.S# = T4.S# AND T4.C# = ‘004’
WHERE student.S#=SC.S# and
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) +
ISNULL(T4.score,0)
NOT IN
(SELECT
DISTINCT
TOP 15 WITH TIES
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) +
ISNULL(T4.score,0)
FROM sc
LEFT JOIN sc AS T1
ON sc.S# = T1.S# AND T1.C# = ‘k1’
LEFT JOIN sc AS T2
ON sc.S# = T2.S# AND T2.C# = ‘k2’
LEFT JOIN sc AS T3
ON sc.S# = T3.S# AND T3.C# = ‘k3’
LEFT JOIN sc AS T4
ON sc.S# = T4.S# AND T4.C# = ‘k4’
ORDER BY ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) +
ISNULL(T4.score,0) DESC);

  • ISNULL(T4.score,0)
          FROM sc
                LEFT JOIN sc AS T1
                          ON sc.S# = T1.S# AND T1.C# = ‘k1’
                LEFT JOIN sc AS T2
                          ON sc.S# = T2.S# AND T2.C# = ‘k2’
                LEFT JOIN sc AS T3
                          ON sc.S# = T3.S# AND T3.C# = ‘k3’
                LEFT JOIN sc AS T4
                          ON sc.S# = T4.S# AND T4.C# = ‘k4’
          ORDER BY ISNULL(T1.score,0) + ISNULL(T2.score,0) +
    ISNULL(T3.score,0) + ISNULL(T4.score,0) DESC);

2三 、总计列印各科成绩,各分数段人数:课程ID,课程名称,[100-85],[85-70],[70-60],[
<60]
SELECT SC.C# as 课程ID, Cname as 课程名称
,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 –
85]
,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 –
70]
,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 –
60]
,SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -]
FROM SC,Course
where SC.C#=Course.C#
GROUP BY SC.C#,Cname;

2三 、总计列印各科战绩,各分数段人数:课程ID,课程名称,[100-85],[85-70],[70-60],[
<60]
    SELECT SC.C# as 课程ID, Cname as 课程名称
        ,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS
[100 – 85]
        ,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS
[85 – 70]
        ,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS
[70 – 60]
        ,SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -]
    FROM SC,Course
    where SC.C#=Course.C#
    GROUP BY SC.C#,Cname;

2④ 、查询学终生均成绩及其排行
SELECT 1+(SELECT COUNT( distinct 平均战表)
FROM (SELECT S#,AVG(score) AS 平均成绩
FROM SC
GROUP BY S#
) AS T1
WHERE 平均战绩 > T2.平分成绩) as 排行,
S# as 学生学号,平均成绩
FROM (SELECT S#,AVG(score) 平均战表
FROM SC
GROUP BY S#
) AS T2
O奇骏DE途达 BY 平均战表 desc;

2肆 、查询学一生均成绩及其排名
      SELECT 1+(SELECT COUNT( distinct 平均战绩)
              FROM (SELECT S#,AVG(score) AS 平均成绩
                      FROM SC
                  GROUP BY S#
                  ) AS T1
            WHERE 平均战绩 > T2.等分成绩) as 名次,
      S# as 学生学号,平均战表
    FROM (SELECT S#,AVG(score) 平均战绩
            FROM SC
        GROUP BY S#
        ) AS T2
    O昂科威DEOdyssey BY 平均战表 desc;
 
2伍 、查询各科战绩前三名的笔录:(不考虑成绩并列意况)
      SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数
      FROM SC t1
      WHERE score IN (SELECT TOP 3 score
              FROM SC
              WHERE t1.C#= C#
            ORDER BY score DESC
              )
      ORDER BY t1.C#;
2⑥ 、查询每门课程被选修的上学的儿童数
  select c#,count(S#) from sc group by C#;
2柒 、查询出只选修了一门课程的一切学生的学号和姓名
  select SC.S#,Student.Sname,count(C#) AS 选课数
  from SC ,Student
  where SC.S#=Student.S# group by SC.S# ,Student.Sname having
count(C#)=1;
2⑧ 、查询男士、女子人数
    Select count(Ssex) as 男子人数 from Student group by Ssex having
Ssex=’男’;
    Select count(Ssex) as 女孩子人数 from Student group by Ssex having
Ssex=’女’;
2⑨ 、查询姓“张”的学生名单
    SELECT Sname FROM Student WHERE Sname like ‘张%’;
30、查询同名同性学生名单,并总括同名家数
  select Sname,count(*) from Student group by Sname having 
count(*)>1;;
3① 、一九八五年出生的学生名单(注:Student表中Sage列的花色是datetime)
    select Sname,  CONVERT(char (11),DATEPART(year,Sage)) as age
    from student
    where  CONVERT(char(11),DATEPART(year,Sage))=’1981′;
3② 、查询每门科目标平均成绩,结果按平均成绩升序排列,平均战表一样时,按学科号降序排列
    Select C#,Avg(score) from SC group by C# order by Avg(score),C#
DESC ;
3三 、查询平均成绩超过85的具备学员的学号、姓名和平均战表
    select Sname,SC.S# ,avg(score)
    from Student,SC
    where Student.S#=SC.S# group by SC.S#,Sname having   
avg(score)>85;
3④ 、查询课程名称为“数据库”,且分数低于60的上学的小孩子姓名和分数
    Select Sname,isnull(score,0)
    from Student,SC,Course
    where SC.S#=Student.S# and SC.C#=Course.C# and 
Course.Cname=’数据库’and score <60;
3伍 、查询全部学员的选课景况;
    SELECT SC.S#,SC.C#,Sname,Cname
    FROM SC,Student,Course
    where SC.S#=Student.S# and SC.C#=Course.C# ;
3陆 、查询别的一门科目成绩在陆拾伍分以上的全名、课程名称和分数;
    SELECT  distinct student.S#,student.Sname,SC.C#,SC.score
    FROM student,Sc
    WHERE SC.score>=70 AND SC.S#=student.S#;
3柒 、查询不及格的学科,并按学科号从大到小排列
    select c# from sc where scor e <60 order by C# ;
3八 、查询课程编号为003且课程成绩在捌拾叁分以上的学生的学号和人名;
    select SC.S#,Student.Sname from SC,Student where SC.S#=Student.S#
and Score>80 and C#=’003′;
3⑨ 、求选了课程的学习者人数
    select count(*) from sc;
40、查询选修“叶平”老师所授课程的学习者中,成绩最高的学习者姓名及其成绩
    select Student.Sname,score
    from Student,SC,Course C,Teacher
    where Student.S#=SC.S# and SC.C#=C.C# and C.T#=Teacher.T# and
Teacher.Tname=’叶平’ and SC.score=(select max(score)from SC where
C#=C.C# );
4一 、查询各类学科及相应的选修人数
    select count(*) from sc group by C#;
4二 、查询分歧科目成绩一样的学员的学号、课程号、学生战绩
  select distinct  A.S#,B.score from SC A  ,SC B where A.Score=B.Score
and A.C# <>B.C# ;
4三 、查询每门功战表最佳的前两名
    SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数
      FROM SC t1
      WHERE score IN (SELECT TOP 2 score
              FROM SC
              WHERE t1.C#= C#
            ORDER BY score DESC
              )
      ORDER BY t1.C#;
4④ 、总结每门课程的学员选修人数(当先12人的科目才计算)。须要输出课程号和选修人数,查询结果按人口降序排列,查询结果按人头降序排列,若人数相同,按学科号升序排列 
    select  C# as 课程号,count(*) as 人数
    from  sc 
    group  by  C#
    order  by  count(*) desc,c# 
4⑤ 、检索至少选修两门科指标学生学号
    select  S# 
    from  sc 
    group  by  s#
    having  count(*)  >  =  2
4⑥ 、查询全部学生都选修的教程的课程号和科目名
    select  C#,Cname 
    from  Course 
    where  C#  in  (select  c#  from  sc group  by  c#) 
4⑦ 、查询没学过“叶平”老师教学的任一门科指标上学的小孩子姓名
    select Sname from Student where S# not in (select S# from
Course,Teacher,SC where Course.T#=Teacher.T# and SC.C#=course.C# and
Tname=’叶平’);
4八 、查询两门以上不及格课程的校友的学号及其平均成绩
    select S#,avg(isnull(score,0)) from SC where S# in (select S#
from SC where score <60 group by S# having count(*)>2)group by
S#;
4玖 、检索“004”课程分数小于60,按分数降序排列的同学学号
    select S# from SC where C#=’004’and score <60 order by score
desc;
50、删除“002”同学的“001”课程的成就
delete from Sc where S#=’001’and C#=’001′;

2伍 、查询各科成绩前三名的笔录:(不考虑战表并列情况)
SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数
FROM SC t1
WHERE score IN (SELECT TOP 3 score
FROM SC
WHERE t1.C#= C#
ORDER BY score DESC
)
ORDER BY t1.C#;
2六 、查询每门课程被选修的上学的小孩子数
select c#,count(S#) from sc group by C#;
2柒 、查询出只选修了一门课程的全方位学生的学号和姓名
select SC.S#,Student.Sname,count(C#) AS 选课数
from SC ,Student
where SC.S#=Student.S# group by SC.S# ,Student.Sname having
count(C#)=1;
2⑧ 、查询男子、女子人数
Select count(Ssex) as 男士人数 from Student group by Ssex having
Ssex=’男’;
Select count(Ssex) as 女子人数 from Student group by Ssex having
Ssex=’女’;
2⑨ 、查询姓“张”的学生名单
SELECT Sname FROM Student WHERE Sname like ‘张%’;
30、查询同名同性学生名单,并统计同名家数
select Sname,count(*) from Student group by Sname having
count(*)>1;;
3① 、一九八五年出生的学生名单(注:Student表中Sage列的类型是datetime)
select Sname, CONVERT(char (11),DATEPART(year,Sage)) as age
from student
where CONVERT(char(11),DATEPART(year,Sage))=’1981′;
3二 、查询每门学科的平均成绩,结果按平均战表升序排列,平均成绩同样时,按学科号降序排列
Select C#,Avg(score) from SC group by C# order by Avg(score),C# DESC
;
3叁 、查询平均成绩超乎85的具备学生的学号、姓名和平均成绩
select Sname,SC.S# ,avg(score)
from Student,SC
where Student.S#=SC.S# group by SC.S#,Sname having   
avg(score)>85;
3四 、查询课程名称为“数据库”,且分数低于60的上学的小孩子姓名和分数
Select Sname,isnull(score,0)
from Student,SC,Course
where SC.S#=Student.S# and SC.C#=Course.C# and
Course.Cname=’数据库’and score <60;
3伍 、查询全部学生的选课情状;
SELECT SC.S#,SC.C#,Sname,Cname
FROM SC,Student,Course
where SC.S#=Student.S# and SC.C#=Course.C# ;
3六 、查询任何一门学科战绩在柒拾八分以上的姓名、课程名称和分数;
SELECT distinct student.S#,student.Sname,SC.C#,SC.score
FROM student,Sc
WHERE SC.score>=70 AND SC.S#=student.S#;
3七 、查询不及格的教程,并按学科号从大到小排列
select c# from sc where scor e <60 order by C# ;
3捌 、查询课程编号为003且课程战绩在柒十八分以上的学生的学号和姓名;
select SC.S#,Student.Sname from SC,Student where SC.S#=Student.S# and
Score>80 and C#=’003′;
3玖 、求选了学科的学习者人数
select count(*) from sc;
40、查询选修“叶平”老师所授课程的上学的儿童中,成绩最高的上学的儿童姓名及其战绩
select Student.Sname,score
from Student,SC,Course C,Teacher
where Student.S#=SC.S# and SC.C#=C.C# and C.T#=Teacher.T# and
Teacher.Tname=’叶平’ and SC.score=(select max(score)from SC where
C#=C.C# );
4① 、查询各类科目及相应的选修人数
select count(*) from sc group by C#;
4二 、查询不一样学科成绩同样的学员的学号、课程号、学生成绩
select distinct A.S#,B.score from SC A ,SC B where A.Score=B.Score and
A.C# <>B.C# ;
4③ 、查询每门功战表最佳的前两名
SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数
FROM SC t1
WHERE score IN (SELECT TOP 2 score
FROM SC
WHERE t1.C#= C#
ORDER BY score DESC
)
ORDER BY t1.C#;
4④ 、总计每门课程的学生选修人数(超越11个人的学科才总计)。要求输出课程号和选修人数,查询结果按人头降序排列,查询结果按人头降序排列,若人数相
同,按学科号升序排列
select C# as 课程号,count(*) as 人数
from sc
group by C#
order by count(*) desc,c#
4伍 、检索至少选修两门课程的学习者学号
select S#
from sc
group by s#
having count(*) > = 2
4陆 、查询任何上学的小孩子都选修的科目的课程号和学科名
select C#,Cname
from Course
where C# in (select c# from sc group by c#)
4七 、查询没学过“叶平”老师助教的任一门学科的学员姓名
select Sname from Student where S# not in (select S# from
Course,Teacher,SC where Course.T#=Teacher.T# and SC.C#=course.C# and
Tname=’叶平’);
4⑧ 、查询两门以上不及格课程的同学的学号及其平均成绩
select S#,avg(isnull(score,0)) from SC where S# in (select S# from SC
where score <60 group by S# having count(*)>2)group by S#;
4⑨ 、检索“004”课程分数小于60,按分数降序排列的同桌学号
select S# from SC where C#=’004’and score <60 order by score
desc;
50、删除“002”同学的“001”课程的实际业绩
delete from Sc where S#=’001’and C#=’001′;

 

(转
http://blog.sina.com.cn/s/blog_3d4c358f0100lcf3.html

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